On Jul 31, 11:58 am, Bruno Marchal <marc...@ulb.ac.be> wrote:

>
> > How do we know that 0 has a successor though? If 0 x = x and x -0 = x
> > then maybe s(0)=0 or Ez<>s(0)... Can we disprove the idea that a
> > successor to zero does not exist?
>
> No. 0 is primitive term, and the language allows the term s(t) for all  
> term t, so you have the terms 0, s(0), s(s(0)), etc.

It sounds like you're saying that it's a given that 0 has a successor
and therefore doesn't need to be proved.

> The rest follows from the axioms For all x 0 ≠ s(x), s(x) = s(y) -> x  
> = y (so that all numbers have only one successor.  So you can, prove,  
> even without induction, that 0 has a unique successor, different from  
> itself.
>
> > Sorry, I'm probably not at the
> > minimum level of competence to understand this.
>
> I look on the net, but I see errors (Wolfram's definition is Dedekind  
> Arithmetic!)? On wiki, the definition of Peano arithmetic seems  
> correct. You need to study some elementary textbook in mathematical  
> logic. Most presentation assumes you know what is first order  
> predicate logic. You can google on those terms. There are good books,  
> but it is a bit involved subject and ask for some works. Peano  
> Arithmetic is the simplest example of Löbian theory or machines or  
> belief system. It is very powerful. You light take time to find an  
> arithmetical proposition that you can prove to be true and that she  
> can't, especially without using the technics for doing that. Most  
> interesting theorem in usual (non Logic) mathematics can be prove in  
> or by PA. And PA, like all Löbian machine, can prove its own Gödel  
> theorem (if "I" am consistent then "I" cannot prove that "I "am  
> consistent). The "I" is a 3-I.

Thanks, I'll see if I can nibble on it sometime.

Craig

-- 
You received this message because you are subscribed to the Google Groups 
"Everything List" group.
To post to this group, send email to everything-list@googlegroups.com.
To unsubscribe from this group, send email to 
everything-list+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/everything-list?hl=en.

Reply via email to