On Fri, Dec 27, 2013 at 10:39 PM, Stephen Paul King <
stephe...@provensecure.com> wrote:
> Dear Jason,
>
> ISTM that the line " For each program we have generated that has not
> halted, execute one instruction of it for each (Program p in
> listOfPrograms)" is buggy.
>
> It assumes that the space of "programs that do not halt" is accessible.
> How?
>
We never know a prior if a program will halts or not. However, once a
program has reached a halted stated it is immediately apparent. If the
function name was "willThisProgramHalt()", then I agree it would be a buggy
program. :-)
The UD as I wrote it executes all programs, whether they will halt or not,
but it never wastes time trying to run another instruction of a program
that has halted. This is only an optimization, and I added it only to
reduce the ambiguity of "running another instruction of a program that has
halted".
Jason
>
>
> On Fri, Dec 27, 2013 at 10:09 PM, Jason Resch <jasonre...@gmail.com>wrote:
>
>>
>>
>>
>> On Fri, Dec 27, 2013 at 9:31 PM, Stephen Paul King <
>> stephe...@provensecure.com> wrote:
>>
>>> Hi Jason,
>>>
>>> Could you discuss the "trace of the UD" that LizR mentioned? How is it
>>> computed? Could you write an explicit example? I have never been able to
>>> grok it.
>>>
>>>
>> Bruno has written an actual UD in the LISP programming language. I will
>> write a simple one in pseudo-code below:
>>
>> List listOfPrograms = new List[]; # Empty list
>> int i = 0;
>> while (true)
>> {
>> # Create a program corresponding to the binary expansion of the
>> integer i
>> Program P = createProgramFromInteger(i);
>>
>> # Add the program to a list of programs we have generated so far
>> listOfPrograms.add(P);
>>
>> # For each program we have generated that has not halted, execute one
>> instruction of it
>> for each (Program p in listOfPrograms)
>> {
>> if (p.hasHalted() == false)
>> {
>> executeOneInstruction(p);
>> }
>> }
>>
>> # Finally, increment i so a new program is generated the next time
>> through
>> i = i + 1;
>> }
>>
>>
>> Any program, and whether or not it ever terminates can be translated to a
>> statement concerning numbers in arithmetic. Thus mathematical truth
>> captures the facts concerning whether or not any program executes forever,
>> and what all of its intermediate states are. If these statements are true
>> independently of you and me, then the executions of these programs are
>> embedded in arithmetical truth and have a platonic existence. The first,
>> second, 10th, 1,000,000th, and 10^100th, and 10^100^100th state of the UD's
>> execution are mathematical facts which have definite values, and all the
>> conscious beings that are instantiated and evolve and write books on
>> consciousness, and talk about the UD on their Internet, etc. as part of the
>> execution of the UD are there, in the math.
>>
>> Jason
>>
>>
>> --
>> You received this message because you are subscribed to a topic in the
>> Google Groups "Everything List" group.
>> To unsubscribe from this topic, visit
>> https://groups.google.com/d/topic/everything-list/sqWzozazMg0/unsubscribe
>> .
>> To unsubscribe from this group and all its topics, send an email to
>> everything-list+unsubscr...@googlegroups.com.
>> To post to this group, send email to everything-list@googlegroups.com.
>> Visit this group at http://groups.google.com/group/everything-list.
>> For more options, visit https://groups.google.com/groups/opt_out.
>>
>
>
>
> --
>
> Kindest Regards,
>
> Stephen Paul King
>
> Senior Researcher
>
> Mobile: (864) 567-3099
>
> stephe...@provensecure.com
>
> http://www.provensecure.us/
>
>
> “This message (including any attachments) is intended only for the use of
> the individual or entity to which it is addressed, and may contain
> information that is non-public, proprietary, privileged, confidential and
> exempt from disclosure under applicable law or may be constituted as
> attorney work product. If you are not the intended recipient, you are
> hereby notified that any use, dissemination, distribution, or copying of
> this communication is strictly prohibited. If you have received this
> message in error, notify sender immediately and delete this message
> immediately.”
>
> --
> You received this message because you are subscribed to the Google Groups
> "Everything List" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to everything-list+unsubscr...@googlegroups.com.
> To post to this group, send email to everything-list@googlegroups.com.
> Visit this group at http://groups.google.com/group/everything-list.
> For more options, visit https://groups.google.com/groups/opt_out.
>
--
You received this message because you are subscribed to the Google Groups
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to everything-list+unsubscr...@googlegroups.com.
To post to this group, send email to everything-list@googlegroups.com.
Visit this group at http://groups.google.com/group/everything-list.
For more options, visit https://groups.google.com/groups/opt_out.
