On Sun, Sep 29, 2019 at 03:27:51PM -0700, 'Brent Meeker' via Everything List 
wrote:
> 
> 
> On 9/29/2019 3:15 PM, Russell Standish wrote:
> 
>     On Fri, Sep 27, 2019 at 06:27:16PM -0700, 'Brent Meeker' via Everything 
> List wrote:
> 
>         When I wrote "lowest" I was assuming the context of MWI...not a single
>         universe.  The Bekenstein bound implies that the Hubble volume has an 
> upper
>         bound for information capacity of it's surface area in Planck units.  
> This
>         number is around 2.4e106.  So as I read Zurek, he thinks this 
> provides a kind
>         of probability cutoff and branches less probable than 0.4e-106 have 
> zero
>         probability.   And, more to the point, in the limit of large N, where 
> N is the
>         number of degrees of freedom in the environment the off diagonal 
> terms of the
>         reduced density matrix go to zero; but this cutoff makes them exactly 
> zero for
>         N>2.41e106.  I haven't figured out many branchings it would take to 
> reach this
>         number, but with some 1e98 particles it wouldn't take very many.
> 
>         Brent
> 
>     Its an interesting idea, and a plausible mechanism for denying the
>     "no cul-de-sac conjecture" and quantum immortality.
> 
>     However, I do have to wonder the significance of a 2.4x10^106 planck
>     distance quare hubble volume. This surely is a geographical factoid
>     rather than of fundamental significance.
> 
> 
> It's not just geographical.  The Bekenstein bound on the information that can
> be contained within a the Hubble sphere depends on how big the sphere is which
> in turn depends on the expansion rate of the universe.  The expansion rate of
> the universe might be a fundamental constant.
> 
> Brent
>

Wouldn't it also depend on when you are observing the universe?


-- 

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Dr Russell Standish                    Phone 0425 253119 (mobile)
Principal, High Performance Coders
Visiting Senior Research Fellow        hpco...@hpcoders.com.au
Economics, Kingston University         http://www.hpcoders.com.au
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