On 5/8/2022 5:39 PM, Bruce Kellett wrote:
On Mon, May 9, 2022 at 10:32 AM Brent Meeker <meekerbr...@gmail.com> wrote:

    On 5/8/2022 5:25 PM, Bruce Kellett wrote:
    On Mon, May 9, 2022 at 10:17 AM Brent Meeker
    <meekerbr...@gmail.com> wrote:

        On 5/8/2022 3:42 PM, Bruce Kellett wrote:
        On Mon, May 9, 2022 at 6:37 AM smitra <smi...@zonnet.nl> wrote:

            On 08-05-2022 05:58, Bruce Kellett wrote:

            > It is when you take the SE to imply that all possible
            outcomes exist
            > on each trial. That gives all outcomes equal status.

            All outcomes can exist without these being equally
            likely. One can make
            models based on more branches for certain outcomes, but
            these are just
            models that may not be correct.


        Such models are certainly inconsistent with the SE. So if
        your concern is that the SE does not contain provision for a
        collapse, then you should doubt other theories that violate
        the SE. You can't have it both ways: you can't reject
        collapse models because they violate the SE and then embrace
        other models that also violate the SE. Either the SE is
        universally correct, or it is not.

            What matters is that such models can be
            formulated in a mathematically consistent way, which
            demonstrates that
            there is n o contradiction. The physical plausibility of
            such models is
            another issue.


        This has been discussed. To allow for real number
        probabilities, the number of branches on each split must be
        infinite.

        I don't think that's a problem.  The number of information
        bits within a Hubble sphere is something like the area in
        Planck units, which already implies the continuum is a just a
        convenient approximation.  If the area is N then something
        order 1/N would be the smallest non-zero probability.  Also
        there would be a cutoff for the off-diagonal terms of the
        density matrix.  Once all the off-diagonal terms are zero
        then it's like a mixed matrix and one could say that one of
        the diagonal terms has "happened".


    As I have pointed out before, a finite number of branches does
    not work because after a certain finite number of splits, one
    would run out of branches to partition in anything like the way
    appropriate for the related probabilities. One cannot go adding
    more branches at that stage without rendering the whole concept
    meaningless. Keeping things finite has its attractions, but it
    does not work in this case.

    I think it depends on how you count splits.  If the number of dof
    within a Hubble volume is finite, then the number of splits
    doesn't grow exponentially.  They get cut off when their
    probability becomes too small.


You are back to your notion of a smallest possible probability. That also runs into problems if you run a long sequence of events where one outcome has a very small probability on each trial. Try tossing a coin N times. The probability of a sequence of N heads is 1/N. What happens when this gets smaller than the smallest allowed probability? Is the next toss somehow forbidden to give head again? You are making the whole notion of probability problematic.

Yes, I can see a concern.  But my back-of-the envelope estimate is that the Hubble volume has the information content of ~10^96 bits. So it would very hard experimentally to flip enough coins to test that limit.  However it would imply that you couldn't create a pseudo-random number generator that could produce random numbers with that many bits.  That would raise the question of how would you tell?  The sequence of numbers of a good pseudo-random number generator look random until you test high order correlations.

Brent

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