Hi all,
I need help tweaking one of my simple macros. I would like to open a
file after I enter a value into a input box. I have files stored in a
specific folder and each one is named like "year_sequence_number", ie:
2011_001. I need a macro which would open a file based on a value I
enter. For example: I enter the value 123 and I get the file 2011_123
opened.
First I wrote this using my basic knowledge:
------------------------------------------------------------------------------------------------
Sub OpenFile()
Dim File As Integer
File = InputBox("Vnesi nalog")
If File = 001 Then
Workbooks.Open Filename:="C:\Users\user\Desktop\2011_001.xlsx"
Else
Exit Sub
End If
End Sub
------------------------------------------------------------------------------------------------
Now is it possible and how to modify this so I wouldn't have to copy
and paste this a thousand times:)
And if possible, I would only like to enter the last three digits as a
value: just 001 and not the full name 2011_001.
Thank you and best regards,
seba
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