ou used range instead of target for your select but I would write it like this
Or even simpler by 
‘dim AType As Range
‘set AType = Range("S8:AL8")
If Not Intersect(Target,range(“s8:al8”) is nothing then

Private Sub Worksheet_Change(ByVal Target As Excel.Range)
Dim SAType As Range
Set SAType = Range("S8:AL8")
If Not Intersect(Target, SAType) Is Nothing Then
On Error Resume Next
   Select Case LCase(Target)'
          Case "amount"
           Target.Offset(1, 0).Resize(296).Style = "Comma"
          Case "percent"
           Target.Offset(1, 0).Resize(266).NumberFormat = "0.000000%"
    End Select
End If
End Sub



Don Guillett
Microsoft MVP Excel
SalesAid Software
dguille...@gmail.com

From: Tiffany 
Sent: Thursday, March 29, 2012 9:52 AM
To: excel-macros@googlegroups.com 
Subject: $$Excel-Macros$$ Problem with Format Change Upon Data Validation 
Change Event

Hi - 

I'm a little new to VBA but have managed to put together a macro that half 
achieves its intended purpose.  

Depending on what is chosen in a data validation cell (any cell in range S8 to 
AL8), the macro is supposed to change the format of 296 cells below the data 
validation cell:
  a.. If "Amount" is chosen in the data validation cell, the format in cells 
below should change to "Comma" style (i.e., 0.00).  This works.   
  b.. If "Percent" is chosen in the data validation cell, the format in cells 
below should change to "0.000000%".  This doesn't work.  I'm stumped since the 
language looks right to me and no debugging error pops up.  Any ideas?

The macro I have now is copied below.  Any help you could provide would be 
greatly appreciated.  


  Private Sub Worksheet_Change(ByVal Target As Excel.Range)


  Dim SAType As Range
  Set SAType = Range("S8:AL8")


  If Not Application.Intersect(Target, SAType) Is Nothing Then
  On Error Resume Next
      Select Case SAType
              Case "Amount"
                  Target.Offset(1, 0).Range("A1:A296").Style = "Comma"
              Case "Percent"
                  Target.Offset(1, 0).Range("A1:A296").NumberFormat = 
"0.000000%"
      End Select
  End If
  End Sub

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