hi..
what i feel is this solution is very complex !!
Rgds//Vabz
On Tuesday, September 11, 2012 7:09:23 AM UTC+5:30, Asa R. wrote:
>
> Hi Mangesh,
>
> I've read your other replies, and as to why you haven't received a formula
> method -- most people don't want to take the trouble on a volunteer basis
> to provide a more complex or difficult solution to a given problem when
> simple solutions exist. Also in business, the simplest solution is the
> best value. But I understand that in learning all aspects of a program,
> sometimes the exercise of solving a problem in various ways is useful.
>
>
>
> I will provide a formula solution for you. Although it could be solved
> several ways, I prefer using an array formula, since it can be written in
> such a way that it can handle a string of text with any number of commas,
> whereas non-array solutions would be limited to a set maximum. However,
> even with the array solution, and even though the array will contain all of
> the parts of the text string, you will only see on your spreadsheet as many
> parts as there are cells in the area you place the array formula (there are
> ways to use array formulas with "too large of arrays" to display on your
> spreadsheet ,as part of other formulas, that are useful; for example
> extracting certain values matching a condition, or summarizing the data (in
> your data, you might want to know how many "Mumbai"s there are, how many
> "32145"s, etc.), without actually displaying in multiple columns all the
> split data.
>
>
>
> · *Select any cell on row 2* of your spreadsheet, *then create the
> following defined names* using the Name Manager (formulas tab in Excel
> 2007+). I recommend *making them Sheet-level names* rather than the
> default Workbook-level.
>
> 1. *Name*
>
> =$A2
>
> 2. *_Name.Terminated*
>
> =Name&","
>
> 3. *_Name.ColumnIdx*
>
>
> =TRANSPOSE(ROW(INDIRECT("1:"&LEN(_Name.Terminated)-LEN(SUBSTITUTE(_Name.Terminated,",","")))))
>
> 4. *_Name.StartPositions*
>
>
> =IF(Name.ColumnIdx>1,FIND(CHAR(1),SUBSTITUTE(Name,",",CHAR(1),_Name.ColumnIdx-1)))+1
>
> 5. *_Name.StopPositions*
>
> =FIND(CHAR(1),SUBSTITUTE(_Name.Terminated,",",CHAR(1),_Name.ColumnIdx))-1
>
> 6. *Name.Columns*
>
> =MID(Name,_Name.StartPositions,_Name.StopPositions-_Name.StartPositions+1)
>
>
>
> *The purpose of using the defined names is to simplify the formula by
> breaking it into steps. Insofar as the steps are referred to more than
> once in the formula, it should make the formula faster to evaluate too. *
> *Name.Columns** is the culmination of our calculation and results in an
> array containing each comma-separated value from column A, divided into
> separate columns.*
>
>
>
> · To display the column-separated values on your spreadsheet, *enter
> the following formula in **B2*:
>
> =Name.Columns
>
>
>
> · Then *highlight from **B2** to the furthest column on row 2
> needed* to display the maximum number of values ever expected. For a
> maximum of 3 values, highlight B2:D2, or for maximum of 10, B2:K2, etc.
>
> · Then hit *F2* (edit cell) and *Ctrl-Shift-Enter* (confirm array
> formula). This confirms a multi-cell array formula over the selected cells.
>
> · Copy the array-entered range from row 2 (e.g. B2:D2) to every
> other row in your table.
>
>
>
> Hope this is of interest,
>
> Asa
>
>
>
>
>
> *From:* excel-...@googlegroups.com <javascript:> [mailto:
> excel-...@googlegroups.com <javascript:>] *On Behalf Of *Mangesh Vimay
> *Sent:* Monday, September 10, 2012 4:04 AM
> *To:* excel-...@googlegroups.com <javascript:>
> *Subject:* $$Excel-Macros$$ Need help - To divide the string into three
> parts
>
>
>
> Hi Friends,
>
>
>
> I need your help to divide the string into three parts.
>
> The description and sample is given below :
>
> [image: Inline image 1]
>
> Waiting for your response.
>
>
>
> Thanks.
>
>
>
> --
> With regards,
>
>
>
> *MaNgEsH*
>
>
>
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