hi.. what i feel is this solution is very complex !!
Rgds//Vabz On Tuesday, September 11, 2012 7:09:23 AM UTC+5:30, Asa R. wrote: > > Hi Mangesh, > > I've read your other replies, and as to why you haven't received a formula > method -- most people don't want to take the trouble on a volunteer basis > to provide a more complex or difficult solution to a given problem when > simple solutions exist. Also in business, the simplest solution is the > best value. But I understand that in learning all aspects of a program, > sometimes the exercise of solving a problem in various ways is useful. > > > > I will provide a formula solution for you. Although it could be solved > several ways, I prefer using an array formula, since it can be written in > such a way that it can handle a string of text with any number of commas, > whereas non-array solutions would be limited to a set maximum. However, > even with the array solution, and even though the array will contain all of > the parts of the text string, you will only see on your spreadsheet as many > parts as there are cells in the area you place the array formula (there are > ways to use array formulas with "too large of arrays" to display on your > spreadsheet ,as part of other formulas, that are useful; for example > extracting certain values matching a condition, or summarizing the data (in > your data, you might want to know how many "Mumbai"s there are, how many > "32145"s, etc.), without actually displaying in multiple columns all the > split data. > > > > · *Select any cell on row 2* of your spreadsheet, *then create the > following defined names* using the Name Manager (formulas tab in Excel > 2007+). I recommend *making them Sheet-level names* rather than the > default Workbook-level. > > 1. *Name* > > =$A2 > > 2. *_Name.Terminated* > > =Name&"," > > 3. *_Name.ColumnIdx* > > > =TRANSPOSE(ROW(INDIRECT("1:"&LEN(_Name.Terminated)-LEN(SUBSTITUTE(_Name.Terminated,",",""))))) > > 4. *_Name.StartPositions* > > > =IF(Name.ColumnIdx>1,FIND(CHAR(1),SUBSTITUTE(Name,",",CHAR(1),_Name.ColumnIdx-1)))+1 > > 5. *_Name.StopPositions* > > =FIND(CHAR(1),SUBSTITUTE(_Name.Terminated,",",CHAR(1),_Name.ColumnIdx))-1 > > 6. *Name.Columns* > > =MID(Name,_Name.StartPositions,_Name.StopPositions-_Name.StartPositions+1) > > > > *The purpose of using the defined names is to simplify the formula by > breaking it into steps. Insofar as the steps are referred to more than > once in the formula, it should make the formula faster to evaluate too. * > *Name.Columns** is the culmination of our calculation and results in an > array containing each comma-separated value from column A, divided into > separate columns.* > > > > · To display the column-separated values on your spreadsheet, *enter > the following formula in **B2*: > > =Name.Columns > > > > · Then *highlight from **B2** to the furthest column on row 2 > needed* to display the maximum number of values ever expected. For a > maximum of 3 values, highlight B2:D2, or for maximum of 10, B2:K2, etc. > > · Then hit *F2* (edit cell) and *Ctrl-Shift-Enter* (confirm array > formula). This confirms a multi-cell array formula over the selected cells. > > · Copy the array-entered range from row 2 (e.g. B2:D2) to every > other row in your table. > > > > Hope this is of interest, > > Asa > > > > > > *From:* excel-...@googlegroups.com <javascript:> [mailto: > excel-...@googlegroups.com <javascript:>] *On Behalf Of *Mangesh Vimay > *Sent:* Monday, September 10, 2012 4:04 AM > *To:* excel-...@googlegroups.com <javascript:> > *Subject:* $$Excel-Macros$$ Need help - To divide the string into three > parts > > > > Hi Friends, > > > > I need your help to divide the string into three parts. > > The description and sample is given below : > > [image: Inline image 1] > > Waiting for your response. > > > > Thanks. > > > > -- > With regards, > > > > *MaNgEsH* > > > > -- > Join official facebook page of this forum @ > https://www.facebook.com/discussexcel > > FORUM RULES (1120+ members already BANNED for violation) > > 1) Use concise, accurate thread titles. 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