Okay, after a bit of research, I've gotten a sort of formula:

=IF((A1)>100000,(A1),(CONCATENATE("AB",(TEXT(A1,"00000")))))

This actually does what I wanted. However, I'd still like to have the final 
number be just a literal number, not a formula.
Assuming A1 is the original number and B1 is this formula, is there a 
formula I can insert into C1 that can paste B1 as a number to D1?

It's mostly a security thing. Always get worried I'll forget and delete my 
formulas.
Also, if there is a shorter better way to do this, please let me know. I'm 
all about the new tricks and better ways.


On Wednesday, February 10, 2016 at 4:52:09 PM UTC-8, Paul Bevins wrote:
>
> Guess, I could add that I've used:
>
> Concatenate ("0000",A1) to give me all my zeros.
> Right (A2,5) function, to reduce the number to just the five digits, or 
> six to give me six digits.
> Then I've used Concatenate ("AB",A1) which will give me all of these 
> numbers, EXCEPT the six digit ones.
> I can't seem to find a way to add the AB to the five digit numbers without 
> ALSO adding it to the six digit ones.
>
> Conversely, If I just add the AB to everything, then Left (A2, 6), then 
> all my AB numbers become just B numbers.
> Maybe a formula to search for B & add A automatically?
> Also, While I can just copy the column and paste values, I'd PREFER the 
> numbers to already be numbers and not formulas looking like numbers. 
> (That's not a biggie, but would be nice.)
>
> On Wednesday, February 10, 2016 at 4:27:58 PM UTC-8, Paul Bevins wrote:
>
>> Hi, I've got an odd problem.
>>
>> I have a database of some 15000 numbers.
>>
>> 10,000 of them (roughly), go from 1 to 10,000.
>> Another 5,000 go from 1,000,000 to 2,000,000.
>>
>> However, the numbers SHOULD AB00001 to AB10000.
>>
>> I need to be able to type the root number in and have Excel decide what 
>> it needs:
>>
>> 1         = AB00001   (7 digits)
>> 22       = AB00022   (7 digits)
>> 333     = AB00333   (7 digits)
>> 4444   =AB04444   (7 digits)
>> 15555 = AB15555   (7 digits)  (excusing that this number won't exist 
>> above 10,000, but five digits.)
>> 100001 = 100001   (6 digits)
>> 200002 = 200002  (same length at 6 digits)
>>
>> I have searched around quite a bit, but have been unable to find the 
>> terms to search for to get these answers.
>> I'm beginning to think I'll need to do it with a VBA script, but am open 
>> to any simple method of doing it, since I type these numbers dozens of 
>> times a day,
>>
>> Anyone have any ideas?
>>
>> Thanks in advance for any help
>>
>> Paul
>>
> 603

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