The proper username format for POP3 is user/domain/mailbox_alias.
Sometimes (un)fortunately the shorter forms work. 

> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:bounce-
> [EMAIL PROTECTED] On Behalf Of Mike Anderson
> Posted At: Wednesday, October 06, 2004 2:41 PM
> Posted To: swynk
> Conversation: Authentication problems using PDA Devices
> Subject: Authentication problems using PDA Devices
> 
> Hello everyone,
> 
> I have a bizarre problem, regarding our Exchange 2003 Server (running
in
> a Windows 2000 Environment), and our external Salespeople using their
> Treo 600 phones.
> 
> All our external employees have Treo 600 devices, running the Palm 5
OS,
> and POP3 Clients - so they are able to connect to any generic POP3
type
> mail server.  Whenever they attempt to pop their mail, it gets back an
> authentication error.  I have full logging turned on - in regards to
the
> POP3 service on the Exchange Server.  The error messages are quite
vague
> - and don't tell me anything regarding the root of the problem.
> 
> Now here is the weird part:  I myself, have this same PDA Phone, and
*I
> CAN* retrieve my e-mail with no problems.  I am using the same phone,
> same software, etc. yet nobody else can get their mail.  I also,
entered
> their accounts into MY phone, to rule out their other phones - and the
> same thing happens.  From the very beginning, I've always been the
> System Administrator, so I considered the possibility that it was a
> permissions problem.  I compared all the other user's settings, to MY
> settings (which groups I belonged to, etc.) and temporarily duplicated
> those settings to the other users.  Also a FYI, I am using the proper
> Username format which is:  DOMAIN\Username - and then of course, just
> the plain password.
> 
> Nothing I tried worked - and I am getting a LOT of heat from my Boss,
> since we spent $600 on each phone - for the sole purpose of our sales
> force, having real-time access to their e-mail.
> 
> Could somebody potentially shed some light on this situation?
> 
> Thanks in advance for your help,
> 
> Mike
> 
> 
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