Tks for reply. I understand the way $test -z "" returns 0 and $test -n "" returns 1. What's puzzling me here is this. $test -z (there is no space after -z, no argment) returns 0 which means 'test command thinks no argment equals to the empty string'. However, $test -n (no space after, no argment) return 0 which means 'test command in this case thinks no argment equals to NO-empty string'. When no argment is given, why test command thinks differenly depending on the options -z and -n. Can you help?? > >On Thu, Dec 19, 2002 at 12:44:30PM +0900, ath1410 wrote: >> $test -z "" >this tests whether the string is empty. in this example it >is, therefor exit code 0. > >> >> But it returns different value after followings. >> >> $test -n "" -- echo$? returns 1 >> $test -n -- " " 0 > >this tests whether the string is NOT empty. the first one >is empty, so exit code is 1. the second one isn't empty. >i guess that you think that spaces count as empty strings, >but a space is a character as everyone (ascii 039), >therefor your string isnt empty and exit code is 0. > >okey? > >have phun;) >miLosh > """""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""" +---------+ * Get your own Jmail account.|URL= http://www.jmail.co.jp |--jmail--| * Get your own home page.|URL= http://www.servance.jp +---------+ * Get your own domain.|URL= http://domaintorou.com/ """"""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""
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