Maybe you already know, but factor doesn't use lists in the same
capacity as scheme and other lisp-variants. Instead it uses sequences.
So to construct a one-item sequence where the first element is f (~=
nil):
IN: scratchpad f 1array
Or just use a literal:
IN: scratchpad { f }
2015-07-03 11:14 GMT+02:00 Iain Gray <iaing...@ednet.co.uk>:
> in Scheme I can evaluate (list ‘()) to get ‘(())
> as a nested null list
>
> Factor supplies nil (+nil+) but I can’t seem to get the above using cons,
> 1list etc.
> is this not the natural way to do this in Factor?
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mvh/best regards Björn Lindqvist
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