On 12/22/06, Larry Brigman <[EMAIL PROTECTED]> wrote: > Trying to debug a problem and my understanding is dim. > > Is the entry that is presented to the kernel equal to > the entry that one would get from readelf -h on a vmlinux compiled with > a physical offset?
On a vmlinux (2.6.19 to be more exact): So you have the startup_32 symbol in the kernel that you want to boot. It should be in arch/i386/kernel/head.S. Then you have the linker script in arch/i386/kernel.vmlinux.lds.S which sets ENTRY() to phys_startup_32 which is startup_32 - PAGE_OFFSET ie the physical address of startup_32. Linux-2.6.19 is known to work to boot into on i386. Use that as a secondary kernel to begin with and when you have that working you can try booting older kernels. I have a small working serial console config if you are interested. The kernel entry point is not everything though. You have purgatory which is a glue layer in between the kernels. It is contained in the kexec-tool and loaded and linked during runtime. So the entry point you will see in kexec (in your first kernel) will most likely be the entry point of purgatory. It took me a while to figure that out and now I have mixed feelings about purgatory... =) / magnus _______________________________________________ fastboot mailing list fastboot@lists.osdl.org https://lists.osdl.org/mailman/listinfo/fastboot
