var y = 1;
fun x => y;
println$ "Hello World " + str x;
++y;
println$ "Hello World " + str x;
proc f(ref a:int) {
println$ a;
}
f &y;
proc h { println "hi"; }
h;
///////
The fun x => y thingo is a functional variable. This is just like a function
accepting a unit, except you don't need to apply it.
The procedure f is accepting a reference argument. This is just a pointer
to the given type, except within the body of the procedure you don't
need to dereference it. You must *pass* a pointer to the procedure however.
And h has no arguments so you can omit the () in the definition.
Of course as usually you can also omit the () in the call.
--
john skaller
[email protected]
http://felix-lang.org
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