Dang .. this works! //// fun apply[t,n] (i:int,a:array[t,n]) => a.[i];
val x = 11,22,33,44; println$ 2 x; println$ x . 2; var i = 1; println$ i x; println$ x . i; ///// As you may know I recently simplified tuple access to (1,2,3) . 1 i.e. you can select the i'th component by just writing . i, but i has to be a literal integer. Used to be tuple.(i). We now it seems, for read access anyhow, we can get rid of the a.[i] notation for subscripting (at least for fetching). -- john skaller skal...@users.sourceforge.net http://felix-lang.org ------------------------------------------------------------------------------ For Developers, A Lot Can Happen In A Second. Boundary is the first to Know...and Tell You. Monitor Your Applications in Ultra-Fine Resolution. Try it FREE! http://p.sf.net/sfu/Boundary-d2dvs2 _______________________________________________ Felix-language mailing list Felix-language@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/felix-language