On 28/04/2015, at 11:36 PM, john skaller wrote:
> I'm giving up: I'm defining it directly in the compiler.
This now works:
////////////////
fun f (x:int) : int => x + 1;
fun g (x:int): string => x.str+"!";
fun h (x:double) :string => x.str+"!";
var fgx = \prod (f,g,h);
println$ fgx (1,2,3.1);
/////////////
Result:
(2, 2!, 3.1!)
I still have to do dup, sums, etc.
\prod (f,g) is the same as f \times g.
However
var tup = f,g,h;
var fgh = \prod tup;
works with the new code, the only way to write that with \times and \otimes is
tup.0 \otimes (tup.1 \times tup.2)
--
john skaller
[email protected]
http://felix-lang.org
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