On 10/17/06, koloa <[EMAIL PROTECTED]> wrote: > > > Hello Jens, just a quick question about your code... > > if i am using this: > > @test = > County.find_by_contents(@params['search_string'],:first_doc=>0,:num_docs=>10)
For starters, :first_doc is now :offset and :num_docs is now :limit, as of Ferret 0.10.0. > do i just setup up numbered links in my view to pass a variable to > first_doc? so if i wanted to get the next set, id do: > > > @test = > County.find_by_contents(@params['search_string'],:first_doc=>@params['10'], > :num_docs=>10) Strange parameter name but yes, that's how you'd do it. > if this is the case, is there an easier way and also a way to count how > many sets or how many pages there are in a table for a given query? > would i just get a total from the array and then divide by 10 docs? > etc...? I'm not sure about easier way but you can get the total number of matching hits from @test.total_hits. On the other hand, @test.size will be the number of hits returned. Hope that answers your question, Dave _______________________________________________ Ferret-talk mailing list [email protected] http://rubyforge.org/mailman/listinfo/ferret-talk
