'a' is a stop word by default (so is 'i'). If you instantiate the query
parser with an Analyzer with no stop words, thusly:
qp3 = Ferret::QueryParser.new(
:analyzer => Ferret::Analysis::StandardAnalyzer.new([])
)
Then qp3.parse('a') (after the appropriate fields call) will return the
desired results.
-Chris
On Thu, Sep 27, 2007 at 10:41:53PM +1000, Andy Shen wrote:
> Hi there,
>
> I am stomped as to why QueryParser's parse method behaves differently
> between query 'a' and 'b'.
> See http://pastie.caboo.se/private/4rlwrecyyow3yl6qtf4tq
>
> Could someone please help me understand why that is the case.
>
> p.s. I also found 'i' produce the same behavour as 'a'
>
> Cheers,
> Andy
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