Hi Thomas,
Here is a bash script I made to do something similar
I’ve converted is so that ffmpeg will cut 5 seconds from the start and 10 from
the end.
#!/bin/bash
#------>>>> Set the input video
input="/path/to/VideoInput1.mp4"
#get fps of input video
eval $(ffprobe -v error -of flat=s=_ -select_streams v:0 -show_entries
stream=duration $input)
# ------>>>> Round input to seconds and set as variable
inputduration=${streams_stream_0_duration%.*}
# ------convertsecs converts seconds to hh:mm:ss
convertsecs() {
((h=${1}/3600))
((m=(${1}%3600)/60))
((s=${1}%60))
printf "%02d:%02d:%02d\n" $h $m $s
}
echo $inputduration
echo $(convertsecs inputduration)
echo $(convertsecs $((inputduration - 10)))
# ------>>>> Set the in (file locations), -ss start encoding here (hh:mm:ss),
-to end encoding here (hh:mm:ss - 10seconds)
ffmpeg -i $input -ss 00:00:05 -to $(convertsecs $((inputduration - 10))) -codec
copy "VideoPath/VideoOutput1.mp4”
#------>>>> End of Bash Script!
It will run ffprobe and get the duration of the input video, convert it to
seconds, convert that to hh:mm:ss then run ffmpeg and cut off 5 seconds from
the start and 10 seconds from the end.
Good luck!
Aidan
> On 19 Jan 2016, at 7:51 am, [email protected] wrote:
>
> Hi
>
> I am been trying almost every combination of switches to be able to cut 5
> sec from the start and 5 sec from the ending of variable length mp4 files.
>
> I have not been successful at doing either. I guess I really don't
> understand the usage. I have more than 100 files to do.
>
> Can anyone suggest a command string that will work?
>
>
>
> Thanks
>
> Thomas
>
>
>
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