What I meant was that it uses 16 bits to store 12 bits of information. So if
you start with a 2000x3000 resoluation image for 3 channels at 8 bits you
get 18MB. To go to 12 bit it seems that you would go to 27MB, a 50% increase
in size. But in fact you have to store the 12 bit image in a 16 bit format
using 36MB or a 100% increase in size. Maybe I shouldn't have used
information?
Jack Phipps
Applied Science Fiction
-----Original Message-----
From: shAf [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 05, 2001 3:50 PM
To: [EMAIL PROTECTED]
Subject: RE: filmscanners: Re: bit depth and dynamic range
Jack writes ...
> ...
> Nikon scanner scans at 12 bits (12x3=36) and if you
> want the extra bit depth it stores at 16 bits (48 bits).
> So the file size increases by 100% (if it is a tif for
> example) while information increases by 50%. ...
I have to ask what you are calling "information"? A 50% increase
would seem to imply 8bit versus 12bit(?) Whereas 256 values/channel
vs 4096 values would imply a 1600% increase in information(?) I
probably misunderstood you somehwere(?)
shAf :o)