On Tue, Aug 2, 2016 at 2:02 PM, Campbell, Ian <i.campbel...@imperial.ac.uk> wrote: > > I've tried the mean-square and RMS values, but they're both orders of > magnitude away from the residual returned by '.sweep'. As such, can you > please tell me the formula used by '.sweep' to compute the residual, so that > I may use the same one?
I think it's the L2 norm of "A * x - b" without any normalization, where x is the variable value before the linear solve. See, https://github.com/usnistgov/fipy/blob/develop/fipy/solvers/solver.py#L135 -- Daniel Wheeler _______________________________________________ fipy mailing list fipy@nist.gov http://www.ctcms.nist.gov/fipy [ NIST internal ONLY: https://email.nist.gov/mailman/listinfo/fipy ]