Hi, Firebird 3 can someone tell me how to work with substring similar? SELECT substring('abc' similar 'a' escape '#') FROM RDB$DATABASE raise an error "Invalid SIMILAR TO pattern" SELECT substring('ab11c' similar '[0-9]+' escape '#') FROM RDB$DATABASE raise an error "Invalid SIMILAR TO pattern" what i am doing wrong? how this pattern should looks like? regards, Karol Bieniaszewski
[firebird-support] substring similar - "Invalid SIMILAR TO pattern"
liviuslivius liviusliv...@poczta.onet.pl [firebird-support] Mon, 03 Dec 2018 00:54:35 -0800
- [firebi... liviuslivius liviusliv...@poczta.onet.pl [firebird-support]