On Oct 20, 5:50 am, pagod <thepa...@googlemail.com> wrote: > Hi, > > I've been using Firebug for a while to debug my web pages and it's > really a great tool, saved me hours/days/weeks of painstaking digging > through DOM and javascript code... > > There is however one feature that'd be *really* useful and that I > haven't been able to uncover -- probably it's just here waiting for > someone to tell me it's here... Anyway, here goes: is there a way to > restrict Firebug's actions (like e.g. break on error, error display) > to pages originating from certain servers/domains? As an example, I'm > designing a page that loads an external page (from another server in > the company) within an iframe. This "subpage" contains buggy > javascript code (perhaps due to the fact that it's not expecting to be > loaded into an iframe...) and Firebug breaks on each of these errors. > And of course, what I'm interested in is my code, not that of this > other page...
One different approach is to look for the error entries in the Console panel, then click the red break-on-error button to the left of the entry. > Another annoying effect is that when loading pages like e.g. iGoogle, > Firebug displays several errors on the console that occur on these > pages. I therefore tend to ignore the message that appears at the > bottom right corner of the window because most of the errors it > reports are also not mine... > > So what I'd like to be able to do is tell Firebug to only supervise > code located on my very own computer, and nothing else. Is that > possible? Not that I know. jjb > > Thanks in advance! > > Pagod -- You received this message because you are subscribed to the Google Groups "Firebug" group. To post to this group, send email to fire...@googlegroups.com. To unsubscribe from this group, send email to firebug+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/firebug?hl=en.
