Does the following command look right to you all?
We are trying to forward (open up) a port on our firewall so that an outsider can test web pages on our internal test server:
ipmasqadm portfw -a -P tcp -L 216.*.*.* 80 -R 192.*.*.*:8000
(where the 216 number is the firewall and the 192 number is the internal test server)
I thought we were simply forwarding Port 80 of the firewall to Port 8000 on the internal server so that the user from outside would simply type: http://192.*.*.*:8000 and get the test server. Someone else says that the outsider types http://216.*.*.*:8000 and gets the test data. Neither one of them work now anyway so something is wrong even if I am unclear on the concept.
Thanks for your patience with me.
Catherine Rowland
System Administrator
