It's important to remember i don't expect a perfect circle. Perhaps my
terminology is weak, i mean a ring of circles
http://andreas.rayon.no/temp/circleOfCircles.png
- A
Ron Wheeler wrote:
These circles will overlap each other.
If this is not what you want, then Charles is right. It is not
possible to do what Andreas seems to be describing.
Perhaps Andreas should draw a picture by hand of what he actually
wants this to look like.
Ron
Ron Wheeler wrote:
From what is said, is it true that you want to take a large circle,
divide it up into a random number of pie shaped slices and then use
the outer edges of the pies as diameters of smaller circles so that
when the smaller circles are drawn, they form a circle of circles.
If so you need to decide how to break 360 degrees up into a number of
angles.
Start at the 0 point (wherever you want the start to be) and find the
intersection a line drawn from the center of the circle to the edge
and then do the same for the next radius. The 2 points form the
diameter of the first small circle. The small circle's radius is half
the distance between the points and the centre of the small circle is
at the midpoint between these 2 points.
Do this for each pair of radius lines and you will have a circle of
circles.
Ron
Andreas R wrote:
To reiterate, there can be *any* number of circles of *any* size.
The aim is to create a circular chain of circles where the overall
diameter is a result of the circumference of the chain.
Alias™ wrote:
And does the number of circles vary? Will it always be the same
number?
On 17/09/06, Andreas R <[EMAIL PROTECTED]> wrote:
The circles can be any size.
Alias™ wrote:
> Ok, are the circles all the same size, or do they have the same
length?
>
> Alias
>
> On 17/09/06, Andreas R <[EMAIL PROTECTED]> wrote:
>>
>> smart people, help a less smart one out:
>>
>> I'm faced with a problem similar to the seven circles theorem
>> (http://mathworld.wolfram.com/SevenCirclesTheorem.html) in that
i need
>> to arrange x number of circles along a circular path, making
sure they
>> all touch their two neighbors. In this way, the path's radius
is NOT
>> given, but is rather made up from the sum of all the circles'
diametres.
>>
>> I've boiled the problem down to this: I have a line of x length
with y
>> number of segments of nonuniform length. I know the final
length of the
>> line because i know the length of each individual segment.
>>
>> Now, i need to "bend" this line so that the end of the final
segment
>> touches on the beginning of the first one. As such, each
segment must
be
>> given an angle somehow based on the overall amount of segments and
their
>> individual lengths.
>>
>> Beyond this, i'm stumped. I've been pouring over mathworld and
google
>> looking for such bendyness, and i've come up empty handed.
>>
>> Anyone have suggestions, possible solutions?
>>
>> Thanks,
>>
>> - A
>> _______________________________________________
>> [email protected]
>> To change your subscription options or search the archive:
>> http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
>>
>> Brought to you by Fig Leaf Software
>> Premier Authorized Adobe Consulting and Training
>> http://www.figleaf.com
>> http://training.figleaf.com
>>
> _______________________________________________
> [email protected]
> To change your subscription options or search the archive:
> http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
>
> Brought to you by Fig Leaf Software
> Premier Authorized Adobe Consulting and Training
> http://www.figleaf.com
> http://training.figleaf.com
_______________________________________________
[email protected]
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com
_______________________________________________
[email protected]
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com
_______________________________________________
[email protected]
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com
_______________________________________________
[email protected]
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com
_______________________________________________
[email protected]
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com
_______________________________________________
[email protected]
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com
