Thats actually pretty good. Thanks for that :) I've added some additional
logic to it, so I also don't get back a previously produced result too.

Thanks :)

- e.

On 12/5/06, Danny Kodicek <[EMAIL PROTECTED]> wrote:

> I thought of something.
>
> function randomRange( min, max, currNum):Number {
>    if(Math.random()>0.5){
>         max=currNum;
>    }else{
>         min=currNum;
>    }
>    return Math.round(Math.random()*(max-min))+min;
> };
>

That's going to skew your function something chronic. No, what you need is
this:

function randomRange(min, max, curr) {
var nNum = Math.round(Math.random() * (max-min-2) ) + min
if (nNum>=curr) {nNum+=2}
return nNum
}

Danny

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