function getNodes(xmlDoc, tagname, xmlObjArray, isFirst):Array{
if(xmlObjArray == null){
yourArr = new Array();
}else{
yourArr = xmlObjArray;
}
if(xmlDoc.hasChildNodes()){
for(var i=0; i < xmlDoc.childNodes.length; i++){
if( (xmlDoc.childNodes[i].nodeType == 1) &&
(xmlDoc.childNodes[i].nodeName ==
tagname)){
//code here
}
yourArr.push(page);
}
getNodes(xmlDoc.childNodes[i], tagname,
yourArr);
}
}
if (isFirst == true) {
//trace("finished!");
return yourArr;
}
Does this help?
Andrew
On 26 Feb 2007, at 16:43, Tom Klepl wrote:
Thanks for the reply.. unfortunately this only returns matching
nodes below the parent node specified. What I need is to crawl the
XML tree and find ALL matching nodes, regardless of where they are
in the tree.
Tom
Quoting [EMAIL PROTECTED]:
I believe:
XPathAPI.selectNodeList(node,"/*/nameOfNode");
will return an array of all child nodes with "nameOfNode" as their
nodeName
On Feb 23, 2007, at 5:39 PM, Tom Klepl wrote:
Hi..
I am working on a project currently and I'm using Macromedia's
XPathAPI. However, I need to recursively search one of my XML
files which is 4 or 5 levels deep. The search I want to perform
should return all nodes with a specified name, no matter where
they are in the hierarchy.
Can anyone suggest/point me to a solution? I don't want to use
xfactorstudio's API due to its size. I am thinking of extending
XPathAPI.
Thanks.
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