Hi,
when the superclass has a default contructor without parameters, there is no
need to call it explicitly.
I'd like to turn it around though, no matter what or how you have defined
them, always call them explicitly for clarity's sake and self documentation.
greetz
JC
On 8/14/07, Alan MacDougall <[EMAIL PROTECTED]> wrote:
>
> Compare these two situations:
>
> class SuperClass
> {
> private var list:Array;
>
> public function SuperClass()
> {
> list = new Array();
> }
> }
>
> class SubClass extends SuperClass
> {
> // when instantiated, the list variable is automatically initialized
> }
>
> This is as it should be. The superclass constructor is executed when the
> subclass is instantiated, as long as the subclass doesn't override it.
>
> class Button
> {
> private var clip:MovieClip;
>
> public function Button(clip:MovieClip)
> {
> clip.onRelease = Delegate.create(this, handlerMethod);
> }
> }
>
> class SpecialButton extends Button
> {
> // does not override the superclass constructor
> }
>
> In this case, code such as "var foo:Button = new SpecialButton(clip);"
> does NOT execute the superclass constructor. Instead, I need this:
>
> class SpecialButton extends Button
> {
> public function SpecialButton(clip:MovieClip)
> {
> super(clip); // now it works
> }
> }
>
> My understanding of inheritance is that I should not need to explicitly
> call the superclass constructor as long as I'm not overriding or
> extending that method of the superclass. What gives? Is it a language
> quirk?
>
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