Hi Hans,
'super' refers to the instance, but your static _test isn't part of
the instance, it is part of the class (technically, of the constructor
function). Imagine it as this.prototype.prototype, although it
technically isn't the same (well, maybe it is, I haven't tested it).
It behaves like super would, with the exception of the super() call of
the constructor.
To do what you want, super.constructor._test would probably work (but
again, I haven't tested it).
HTH,
Mark
On 8/20/07, Hans Wichman <[EMAIL PROTECTED]> wrote:
> Hi,
>
> lets say i have a superclass:
>
> class SuperClass {
> private var _test:String = null;
> }
>
> and a subclass:
>
> class SubClass {
> private function _testFunction () {
> super._test = "foo";
> trace (super._test);
> }
> }
>
>
> this traces undefined.
>
> If I remove the super. it works, but I like to know when I'm referencing
> super class fields.
>
> It is fixed as well, when I nicely wrap the setting of _test in a function,
> as I should, but I'm still wondering why it fails.
>
> Any ideas?
>
> greetz
> JC
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