I find this fast and reliable...
var lines:Array = str.split
("\r\n").join("\n").split("\r").join("\n").split("\n");
On 9/13/07, Mark Winterhalder <[EMAIL PROTECTED]> wrote:
>
> var lines : Array = (str.indexOf( "\r\n" ) > -1) ? str.split( "\r\n" )
> : str.split( "\n" );
>
> Or, if you want to take MacOS 9 into account:
>
> var lines : Array;
> if( str.indexOf( "\r\n" ) > -1 ) {
> lines = str.indexOf( "\r\n" );
> } else if( str.indexOf( "\n" ) > -1 ) {
> lines = str.split( "\n" );
> } else if( str.indexOf( "\r" ) > -1 ) {
> lines = str.split( "\r" );
> } else {
> lines = str;
> }
>
> (You don't actually need the "default", splitting on a non-existing
> string should return an array of length 1. It's just more clear that
> way.)
>
> HTH,
> Mark
>
>
> On 9/12/07, Danny Kodicek <[EMAIL PROTECTED]> wrote:
> > I'm looking for a simple, reliable method for splitting a string into
> its
> > constituent lines (at the hard line breaks - this isn't a text wrapping
> > thing). The problem is that line breaks could be Chr(10) or Chr(13), or
> > indeed both. I've done this:
> > myArr =
> > myStr.split(String.fromCharCode(10)).join(String.fromCharCode
> (13)).split(Str
> > ing.fromCharCode(13))
> >
> > I'm guessing I'm better off going the RegEx route, but I was wondering
> if
> > there's a quicker, simpler way.
> >
> > Danny
> >
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