Because your second query returns an empty list instead of null.
So, instead of checking for null, just check the length of the result.
trace(describeType(xml1.lobby)); trace(xml1.lobby.length()); // 1
trace(describeType(xml2.lobby)); trace(xml2.lobby.length()); // 0
The first time I noted this it also confused me. I think it's clearly a
feaure, though, and it actually makes sense to me, because, otherwise, you
couldn't safely write something like this:
trace(xml1.lobby.user);
trace(xml2.lobby.user);
If at some point your query returned null, you'd have to check for null
explicitly or wrap almost every single line of code that manipulates XML in
try/catch to make sure it doesn't blow up because of a null reference error.
Cheers
Juan Pablo Califano
2010/2/6 Alexander Farber <alexander.far...@gmail.com>
> Hello,
>
> I've prepared a simple test case for my problem:
>
> var xml1:XML =
> <pref>
> <lobby>
> <user id="DE2" name="Alex" avatar="2_1211369175.jpg"/>
> </lobby>
> <game id="0"/>
> </pref>;
>
> var xml2:XML =
> <pref>
> <user0 id="DE2" name="Alex" avatar="2_1211369175.jpg"/>
> </pref>;
>
> if (xml1.lobby)
> trace('1: in the lobby');
>
> if (xml2.lobby)
> trace('2: in the lobby');
>
> Why does this print the 2nd line too?
>
> 1: in the lobby
> 2: in the lobby
>
> I keep trying and also look in the debugger and just don't get it...
>
> Thank you
> Alex
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