On 12/10/2011 21:49, Kenneth Kawamoto wrote:
Not sure if this is the "best" way but you can do:
var xml:XML = <my_xml>
<row id="a" />
<row id="b" />
<row id="c" />
</my_xml>;
xml.row.(@id == "a").children = xml.row.(@id != "a");
xml.setChildren(xml.row.(@id == "a"));
trace(xml);
// trace
<my_xml>
<row id="a">
<row id="b"/>
<row id="c"/>
</row>
</my_xml>
Kenneth Kawamoto
http://www.materiaprima.co.uk/
Thanks - that works well and I hadn't considered using setChildren. It's
a great solution that shows my simplification was too simple!
If I have
<my_xml>
<row id="a" parent="a" />
<row id="b" parent="a" />
<row id="c" parent="a" />
<row id="d" parent="d" />
<row id="e" parent="d" />
<row id="f" parent="d" />
</my_xml>
but want
<my_xml>
<row id="a" parent="a">
<row id="b" parent="a"/>
<row id="c" parent="a"/>
</row>
<row id="d" parent="d">
<row id="e" parent="d"/>
<row id="f" parent="d"/>
</row>
</my_xml>
then it's closer to the real-life scenario and a bit harder.
Thanks for the solution.
Paul
On 11/10/2011 14:53, Paul Andrews wrote:
What's the best way to turn
this:
myXMLNode =
<my_xml>
< row id="a" />
< row id="b" />
< row id="c" />
</my_xml>;
into:
<my_xml>
< row id="a">
< row id="b" />
< row id="c" />
</row>
</my_xml>
Using some E4X?
It's not so much a case of adding b and c as children of a, but of
removing them so I don't end up with:
<my_xml>
< row id="a">
< row id="b" />
< row id="c" />
</row>
< row id="b" />
< row id="c" />
</my_xml>
Paul
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