Use this method and put the stuff inside this function. Here the Object is a row
override public function set data(value :Object){
super.data = value;
// your code
// your code
}
Thanks,
with Regards,
Jitendra Jain
________________________________
From: Tim Hoff <[EMAIL PROTECTED]>
To: flexcoders@yahoogroups.com
Sent: Tuesday, 21 October, 2008 7:10:02 AM
Subject: [flexcoders] Re: How can I make an ItemRenderer on a Datagrid react to
a row selection?
Shoot, don't even worry about the rowIndex, just attach the data object
to the event.
-TH
--- In [EMAIL PROTECTED] ups.com, "Tim Hoff" <[EMAIL PROTECTED] > wrote:
>
>
> Yeah, you would be hosed if a different type of list was used. If
> you're using CHANGE, which is generic for list base, have the parent
> class dispatch a custom event, on change, with the row index. The
> parent class will always know what kind of list is being used. Then in
> the itemRenderer listen for the custom event and compare the rowIndex
to
> listData.rowIndex. This is so much easier to handle through the data,
> but some don't care for the decorator pattern.
>
> -TH
>
> --- In [EMAIL PROTECTED] ups.com, João joao.saleiro@ wrote:
> >
> > I solved it by implementing the IDropInListItemRend erer and
listening
> to
> >
> > DataGrid(listData. owner).addEventL istener(ListEven t.CHANGE,
> > listChangeHandler)
> >
> > It's not a best practice, but for now it's enough.
> >
> > JS
> >
> > --- In [EMAIL PROTECTED] ups.com, Jo�o joao.saleiro@ wrote:
> > >
> > > Hi,
> > >
> > > I have a Datagrid with several rows and columns. I am using
> > > ItemRenderers on the cells. I need that a specific ItemRenderer
> > > changes the way it looks when the row where he's in is selected.
How
> > > can I achieve that?
> > > Is it possible to make the itemrenderer know that and react in
real
> > > time? Or is it preferable to extend the DataGrid?
> > >
> > > Thanks,
> > >
> > > João Saleiro
> > >
> >
>
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