eeks , I did that , the links dont appear .
This is my Code .
for (var i:int=0;i<xlColumns.length();i++) { //loop over the xmlList
xmlColumn = xlColumns[i];
oColumnDef = new Object();
oColumnDef.dataField = xmlColumn.localName();
var urlItemRenderer: ClassFactory = new ClassFactory(urlRenderer) ;
oColumnDef.width = 100;
oColumnDef.itemRenderer = urlItemRenderer;
oColumnDef.sortable = true;
oColumnDef.visible = true;
oColumnDef.editable = false;
oColumnDef.wordWrap = false;
break;
urlRenderer.mxml
<?xml version="1.0" encoding="utf-8"?>
<mx:LinkButton xmlns:mx="http://www.adobe.com/2006/mxml";
label="Click On Me"
click="navigateToURL(new URLRequest('rediff.com'))"/>
--- On Thu, 6/4/09, Tim Hoff <timh...@aol.com> wrote:
From: Tim Hoff <timh...@aol.com>
Subject: [flexcoders] Re: Creating Link inisde a Data Grid Collumn
To: flexcoders@yahoogroups.com
Date: Thursday, June 4, 2009, 1:05 PM
If you're creating the column in AS, you'll need to use ClassFactory for the
itemRenderer:
var urlItemRenderer: ClassFactory = new ClassFactory( com.myPath. urlRenderer) ;
urlItemRenderer. properties = { myItemRendererPubli cProperty: myProperty };
myColumnID.itemRend erer = urlItemRenderer;
-TH
--- In flexcod...@yahoogro ups.com, guess what <myworld100us@ ...> wrote:
>
>
> I want to show link inisde of my Data Grid Columnm . I know i could use item
> renderer . if I try to use it directly in flex file it works fine, meaning if
> i have static columns ,Since my collumns are beeing built dynamicaly . I use
> action Script . I think I am doing soemthing wrong with the script . Can
> anyone help me .
>
> I assume this should be as simple as this . Should urlRenderer be Action
> script file or can anyone explain how do i do this .
> column.itemRenderer = urlRenderer
>
