Re: [flexcoders] Difference between two dates

Mon, 26 Jun 2006 12:33:50 -0700

http://jeff.mxdj.com/datediff_for_actionscript.htm

perhaps this would be helpful.

DK

On 6/26/06, Kelly Birr <[EMAIL PROTECTED]> wrote:
If you do not wish to change the Date class so it will conform to a (terrible) standard, I can sort of understand that.  
 
Would you please consider the possibility of adding a DateTime or Date2 class in Flex 2.1 that works like a primitive type.  Or better yet, make the new class be Date and the standards-compliant one called EcmaDate or EDate or CDate or something like that. :)
 
- Kelly

From: flexcoders@yahoogroups.com [mailto:flexcoders@yahoogroups.com] On Behalf Of Daniel Tuppeny
Sent: Monday, June 26, 2006 1:03 AM
To: flexcoders@yahoogroups.com

Subject: RE: [flexcoders] Difference between two dates

> Since the Date class is specified by the EcmaScript-262 standard, we're not going to change it
 
That's fair enough, but as things are (without a utility class to do this stuff), I can see there being a whole bunch of "buggy" implementations of date stuff in Flex over the coming months, which will be spread amongst developers via sites like CodeProject!! :-(

From: flexcoders@yahoogroups.com [mailto:flexcoders@yahoogroups.com] On Behalf Of Gordon Smith
Sent: 24 June 2006 00:01
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Difference between two dates

Since the Date class is specified by the EcmaScript-262 standard, we're not going to change it. But it sounds like we should consider adding a flex.utils.DateUtils class in the future to make date manipulation easier.

 

- Gordon

 

From: flexcoders@yahoogroups.com [mailto: flexcoders@yahoogroups.com] On Behalf Of Pan Troglodytes
Sent: Friday, June 23, 2006 8:53 AM
To: flexcoders@yahoogroups.com
Subject: Re: [flexcoders] Difference between two dates

 

Well, it helped when I figured out I could do things like date.date += 12 and it would automatically correct for rolling over months/years.  But at the very least, there needs to be a built-in daysBetween function.  Yes, yes, I know you can do the getTime() arithmetic.  But every time you have to fall back to that, it feels kludgy.

If I were redesigning it, it wold at least ook like this:

dayOfWeek - what used to be called day
day - day in month (used to be called date)
month - 1 based like day (what used to be called date) is
hour/minute/second/millisecond - singular (if hour is plural, why not "months"?)
year - why fullYear?  I mean, c'mon, do people really expect something called "year" to be two digits or what?
daysBetween(laterDate:date) - laterDate minus this in days

But, alas, it's too late.  There's no way they'll make the change at this late day.

I mean "date".

Haha.

On 6/23/06, Daniel Tuppeny < [EMAIL PROTECTED]> wrote:

I wouldn't disagree!

 

There seems to be no useful functions for manipulating dates. They should copy all the methods and properties from the .NET DateTime class :o)

 

From: flexcoders@yahoogroups.com [mailto:flexcoders@yahoogroups.com] On Behalf Of Pan Troglodytes
Sent: 23 June 2006 16:02
To: flexcoders@yahoogroups.com
Subject: Re: [flexcoders] Difference between two dates

I swear, I really think the date class was designed by a crazy man.  You hear that Adobe? - CRAZY! :D

On 6/23/06, Daniel Tuppeny < [EMAIL PROTECTED]> wrote:

I was using .day instead of .date

 

TFI Friday! =)

 

From: flexcoders@yahoogroups.com [mailto: flexcoders@yahoogroups.com] On Behalf Of Daniel Tuppeny
Sent: 23 June 2006 15:33
To: flexcoders@yahoogroups.com
Subject: RE: [flexcoders] Difference between two dates

I think I need more coffee....

 

The following code (which I'm sure is correct!), returns around 2.8 when I'm expecting around 3.2. Anyone spot my error?

 

 

 

public static function getMonths(startDate:Date, endDate:Date):Number
  {
   if (startDate > endDate)
   {
    var tmp:Date = endDate;
    endDate = startDate;
    startDate = tmp;
   }
   
   var numMonths:Number = 0;
   
   // Get number of months in years
   numMonths += (endDate.fullYear - startDate.fullYear) * 12
   numMonths += endDate.month - startDate.month;
   numMonths += (endDate.day - startDate.day) / 30; // This needs fixing
   
   return numMonths;
  }


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