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From: flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] On Behalf Of Tim Hoff
Sent: Friday, October 27, 2006 5:19 AM
To: flexcoders@yahoogroups.com
Subject: [flexcoders] Re: ItemRenderer - Which dataField from DataGridColumn?Hi Sönke,
You can get the name of the field with the following code. From there you can adjust your itemRenderer conditionally.
if (listData) {
var myListData:DataGridListData = DataGridListData(listData);
var fieldName : String = myListData.dataField;
}don't forget the import:
import mx.controls.dataGridClasses.DataGridListData;
-TH
__________________________________Tim Hoff
Cynergy Systems, Inc.
http://www.cynergysystems.com
Office: 866-CYNERGY
--- In flexcoders@yahoogroups.com, Sönke Rohde <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I need to access the reference to the DataGridColumn within an custom
> ItemRenderer which is implemented via MXML.
> Do I have to extend a special class for my ItemRenderer or can I acccess it
> via "parent"?
> When I trace the parent in my ItemRenderer I get e.g.
> "ListBaseContentHolder7".
> What I need to no is which dataField has to be rendered within my
> ItemRenderer so I can access the right value in my ValueObject.
>
> Here the MXML for the DataGridColumn:
> <mx:DataGridColumn dataField="example" headerText="Header"
> itemRenderer="CustomItemRenderer"
> />
> So how do I know within the class CustomItemRenderer that the dataField is
> "example"?
>
> Thanks,
> Sönke
>
--
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