Excellent, works great. Thank you. Hosey
On 13 Apr 2007 05:38:14 -0700, Michael Schmalle <[EMAIL PROTECTED]> wrote:
Hi, You could also write a custom dataDescriptor that subclasses DefaultDataDescriptor. In that class override the getChildren() method and only return the children you want based on the nodes you want filtered. Peace, Mike On 12 Apr 2007 22:22:04 -0700, dorkie dork from dorktown <[EMAIL PROTECTED] > wrote: > > i see. what i would do is use a lazy loading mechanism. so you only > display the top level branches. when the user opens a branch then you lazy > load the child nodes. when the user opens the branch then you can get the > node they opened and filter the node they opened of all the noshow nodes. > > // in the open node event > > var filteredNode:XML = myTree.selectedNode.myFilter; > myTree.selectedNode = filteredNode; > > actually, i think there is a way to apply a filter on xmllist collection > non destructively. i think maybe you could put your selected node into an > xml list collection and then filter it. if this was AS2 i'd be able to help > you more. > > > On 12 Apr 2007 18:40:43 -0700, hosey hosey < [EMAIL PROTECTED]> > wrote: > > > > Thanks, I dont believe that can work. > > > > If the data is > > <xml> > > <cb title="hello"> > > <noshow notitle="dontshowanything"/> > > <cb title="there"/> > > </cb> > > </xml> > > > > and I set the datasource=data.cb > > > > then the tree appears with hello and all of the following tags. > > > > if I set the datasource =data..cb > > then I get an XMLlist of all of the tags I need , but the first of > > which expands revealing the no show tag > > > > if I set the datasource=data.cb.(nodeName!="noShow").. the first of > > which expands revealing the no show tag > > > > > > Anyways I am looking into creating a filter function, but I think a > > better way is to extned a renderer...but I dont know yet.... > > > > Thanks > > Hosey > > > > -- Teoti Graphix http://www.teotigraphix.com Blog - Flex2Components http://www.flex2components.com You can find more by solving the problem then by 'asking the question'.
