Whoa... I didn't realize $ was a valid identifier character... that's
interesting.
On 6/1/07, Gordon Smith <[EMAIL PROTECTED]> wrote:
Alex meant to say "If a method is overridden, you can NOT skip around
the override like you can in some other languages." And you can't directly,
with super.super. But you can, indirectly.
The way the framework codes around the lack of super.super is to use the
following pattern:
class A
{
function f()
{
doSomething();
}
}
class B extends A
{
// This will hide A's f()
override function f()
{
doSomethingElse();
}
// But this makes A's f() available as B's $f
final function $f()
{
super.f();
}
}
class C extends B
{
override function f()
{
$f(); // call A's f() -- which is effectively super.super.f()
}
}
Using $ in the name is just a convention which indicates that you're
getting the original, un-overridden function. We also make it final to
guarantee that it remains un-overridden.
- Gordon
------------------------------
*From:* flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] *On
Behalf Of *Alex Harui
*Sent:* Wednesday, May 30, 2007 2:10 PM
*To:* flexcoders@yahoogroups.com
*Subject:* RE: [flexcoders] Re: Is there any way to call
super.super.method in AS3?
Sorry, but I think you're wrong or misunderstood. If a method is
overridden, you can skip around the override like you can in some other
languages
------------------------------
*From:* flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] *On
Behalf Of *justinbuser
*Sent:* Wednesday, May 30, 2007 10:50 AM
*To:* flexcoders@yahoogroups.com
*Subject:* [flexcoders] Re: Is there any way to call super.super.method in
AS3?
--- In flexcoders@yahoogroups.com, "wpding" <[EMAIL PROTECTED]> wrote:
>
> I want to override a method of a super class. and I can use
> super.method to invoke the corresponding method of the super class.
>
> But how i can call a method of the super super class.
> for example.
> Class A{
> protected function myMethod(){}
> }
> Class B extends A{
> override protected function myMethod(){}
> }
>
> Class C extends B{
> override protected function myMethod(){}
> }
>
> Is it possible to call A.myMethod in the function C.MyMethod?
>
> Thanks
>
Yes, exactly how you wrote it. However in order to have the top level
function actually run before adding methods etc... with level 2 you need to
call super.myMethod(); from B or not override it at all in B to be able to
access it's functionality! from C. In other words, if you override a
function and then try to override it again in a class extending the one with
the original override and don't call the super version in the intermediate
class then you end up with an empty function at the end.
JjB
-#As always I could be completely wrong, but it's not likely#-
