This method doesn't work, or? The note in the help seems to imply, that we want to override this method. Maybe it is just a stub?
Note: Methods of the Object class are dynamically created on Object's prototype. To redefine this method in a subclass of Object, do not use the override keyword. For example, A subclass of Object implements function isPrototypeOf():Boolean instead of using an override of the base class. Cheers Ralf. On Fri, Feb 15, 2008 at 7:15 PM, Johannes Nel <[EMAIL PROTECTED]> wrote: > > > > > > > prototype chain is in for ecma complience. the white paper is a good source > of info > > > > On Fri, Feb 15, 2008 at 1:03 PM, Roscoe P Coltrane <[EMAIL PROTECTED]> > wrote: > > > > > > > > > > > > > > > What exactly does it mean when the Flex doco says: > > "This method returns true if the object is in the prototype chain of > > the object specified by the the Class parameter." What > > does "prototype chain" mean here? Sorry for my ignorance if this is > > a dumb question. And are you saying this is an obsolete method? > > > > --- In flexcoders@yahoogroups.com, "Gordon Smith" <[EMAIL PROTECTED]> > > wrote: > > > > > > > > > > > > Flex makes almost no use of AS3's old-style prototype-based > > inheritance; > > > it uses the new class-based inheritance. If by "descendant" you > > mean > > > "instance of", use the 'is' operator: > > > > > > var b:Button = new Button(); > > > trace(b is UIComponent); // --> true > > > > > > Gordon Smith > > > Adobe Flex SDK Team > > > > > > ________________________________ > > > > > > From: flexcoders@yahoogroups.com > > [mailto:[EMAIL PROTECTED] On > > > Behalf Of Roscoe P Coltrane > > > Sent: Thursday, February 14, 2008 6:15 AM > > > To: flexcoders@yahoogroups.com > > > Subject: [flexcoders] Example of Object.isPrototypeOf () > > > > > > > > > > > > Could someone give me a working or semi-working example of > > how/when to > > > use isPrototypeOf()? I was thinking that I could query an object > > and > > > if it was a descendent of another object, [the argument to > > > isPrototypeOf()], the method would return true. Not so :) > > Obviously I > > > don't understand the usage of this method. > > > > > > Thanks, > > > Roscoe > > > > > > > > > > > -- > j:pn > \\no comment -- Ralf Bokelberg <[EMAIL PROTECTED]> Flex & Flash Consultant based in Cologne/Germany
