On Mon, 2006-01-09 at 20:25 -0500, Ampere K. Hardraade wrote:
> On January 9, 2006 04:19 pm, Curtis L. Olson wrote:
> > In nasal, I would like to check if a string ends in '.wav'.  Is there an
> > easy way to do this?
> >
> > Thanks,
> >
> > Curt.
> 
> You can try this:
> 
> substr(foo, size(foo) - 5) == ".wav"
> 
> Ampere

Ampere, should that be 
substr(foo, size(foo) - 4) == ".wav" as - 5 will compare the last five
characters in the string?

Anyway, I'm sure that it is just a typo but bound to confuse someone
reading email or the archive.


Regards


George




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