create a 5th class:
public class ItemE : ItemD
{
}
your example would suggest there's reason for it and probably some behavior
that could be in this new class.
On Fri, Jan 29, 2010 at 11:24 PM, mbag <gunnith...@gmail.com> wrote:
> I'm having trouble mapping the following setup in FNH. Any help would
> be appreciated.
>
>
> /***** Classes for Item Hierarchy *****/
>
> public class ItemA
> {
> public string AProperty { get; set; }
> }
>
> public class ItemB : ItemA
> {
> public string BProperty { get; set; }
> }
>
> public class ItemC : ItemB
> {
> public string CProperty { get; set; }
> }
>
> public class ItemD : ItemB
> {
> public string DProperty { get; set; }
> }
>
> /***** Tables for Item Hierarchy *****/
>
> TABLE A (ItemID INT, ItemTypeID INT, AProperty VARCHAR(100))
> TABLE A (ItemID INT, ItemTypeID INT, BProperty VARCHAR(100))
> TABLE A (ItemID INT, ItemTypeID INT, CProperty VARCHAR(100))
> TABLE A (ItemID INT, ItemTypeID INT, DProperty VARCHAR(100))
>
> /***** ItemTypeID to Class *****/
>
> ItemTypeID = 1 --> ItemA
> ItemTypeID = 2 --> ItemB
> ItemTypeID = 3 --> ItemC
>
> ItemTypeID = 4 --> ItemD
> ItemTypeID = 5 --> ItemD
>
>
> /***** ItemTypeID to Table *****/
>
>
> ItemTypeID = 1 --> Data is in Table A
> ItemTypeID = 2 --> Data is in Table A Join B
> ItemTypeID = 3 --> Data is in Table A Join B Join C
>
> ItemTypeID = 4 --> Data is in Table A Join B Join D
> ItemTypeID = 5 --> Data is in Table A Join B Join D
>
>
> I would like to use a Discriminator column (ItemTypeID) but the
> SubClassMap<ItemD> would have to accept either a value of 4 or 5. Is
> this possible?
>
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thanks
cliff
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