AA should be a SubclassMap and you should use the same Type column to discriminate all sub-classes for that hierarchy.
Any other way doesn't really make sense to NHibernate as the base table is telling NHibernate "I'm a class of type AA" then the "AA" table is trying to tell NHibernate, "no actually I'm E", when really its the whole hierarchy that is of type "E" for said row, including the base table for "A". On May 21, 10:14 am, "Mauro D." <mauroeva...@gmail.com> wrote: > I still didn't find any suitable solution to this mapping problem... > > Sorry > Mauro D. > > On 18 Mag, 08:54, "Mauro D." <mauroeva...@gmail.com> wrote: > > > On 17 Mag, 17:02, Felipe Leusin <felipe.leu...@gmail.com> wrote: > > > > Shouldn't AA Map be a SubclassMap? > > > No, if AA is a SubclassMap I can't insert the call to > > > DiscriminateSubClassesOnColumn(xxxxx); > > > because Subclass don't have this method defined. > > > Mauro > > > -- > > You received this message because you are subscribed to the Google Groups > > "Fluent NHibernate" group.To post to this group, send email > > tofluent-nhibern...@googlegroups.com.to unsubscribe from this group, send > > email tofluent-nhibernate+unsubscr...@googlegroups.com. > > For more options, visit this group > > athttp://groups.google.com/group/fluent-nhibernate?hl=en. > > -- > You received this message because you are subscribed to the Google Groups > "Fluent NHibernate" group. > To post to this group, send email to fluent-nhibern...@googlegroups.com. > To unsubscribe from this group, send email to > fluent-nhibernate+unsubscr...@googlegroups.com. > For more options, visit this group > athttp://groups.google.com/group/fluent-nhibernate?hl=en. -- You received this message because you are subscribed to the Google Groups "Fluent NHibernate" group. To post to this group, send email to fluent-nhibern...@googlegroups.com. To unsubscribe from this group, send email to fluent-nhibernate+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/fluent-nhibernate?hl=en.
