You're right, just after I sent the question I
realized I was off-topic, my apologies.
Thank you for the 2 solutions though.
I did try #2, evaluate() and it worked nicely.
I will fiddle with the other solution as well to check
out its limitations.
Thanks, Mike
--- "J.Pietschmann" <[EMAIL PROTECTED]> wrote:
> Mike Kellstrand wrote:
>
> > I want to be able to pass a node name into a named
> template as a param and
> > then operate on it. When I try to use the node
> name param in the template,
> > it gets interpreted as a string and not an actual
> node. i.e.
> >
> > The snipett:
> > <xsl:variable name="x" select="choice"/>
> > <fo:block>a: <xsl:value-of
> select="choice[1]"/></fo:block>
> > <fo:block>b: <xsl:value-of
> select="concat($x,'[1]')"/></fo:block>
> >
> > Will generate:
> > a: {the actual xml data in the 1st choice node}
> > b: choice[1]
>
> That's exactly as it is supposed to work.
> Actually this is an XSLT question, only loosely
> related to
> FOP, and would have better been asked on the XSL
> list:
> http://www.mulberrytech.com/xsl/xsl-list/
>
> Anyway: You expect the XSLT processor to perform
> what's called
> double evaluation: first evaluate "concat($x,'[1]')"
> into
> "choice[1]", then evaluate the latter again. That's
> not the
> way XPath expressions are handled.
>
> > How do I get this to work as intended?
>
> Commonly, two approaches:
> 1. Use
> <fo:block>b: <xsl:value-of
> select="*[name()=$x][1]"/></fo:block>
> Note that this approach works for your specific
> problem but wont
> help you in more general cases.
> 2. Most XSLT processors have an extension function
> which evaluatess
> a string as XPath expression, roughly like
> <fo:block>b: <xsl:value-of
> select="foo:evaluate(concat($x,'[1]'))"/>..
> The exact function name and the necessary
> namespace are processor
> specific, check your processor's manual for
> details.
>
> J.Pietschmann
>
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