Dear Hadi, Dear GAP Forum, Since 192 = 3 X 2^6, for any divisor d of 192, either d or 192/d is a power of 2, so G has a subgroup of order d or of order 192/d by Sylow's Theorem.
Best regards, Derek. On Thu, Sep 11, 2014 at 09:52:39PM +0430, hadi Hooshmand wrote: > Dear All, > > Let $G$ be a group of order 192 and $d$ a positive divisor of it . Is it > true > that there exists a subgroup of $G$ with order or index $d$? > > Is there any GAP code to check the question by an ordinary computer? > Does anyone know the answer? > > Thanks in advance > _______________________________________________ > Forum mailing list > Forum@mail.gap-system.org > http://mail.gap-system.org/mailman/listinfo/forum _______________________________________________ Forum mailing list Forum@mail.gap-system.org http://mail.gap-system.org/mailman/listinfo/forum
