Hi all, I ran into a problem with resolving commandline parameters, due to wildcard expansion by bash.
Consider the following code: for i := 1 to paramcount do writeln(i,': ',paramstr(i)); My program expects input from the commandline in the form scopy source dest when you now specify wildcards on the commandline, they will be expanded by bash, so the output will be like this: bart@simenon:~/LazarusProjecten/ConsoleProjecten/scopy> ./scopy * 1: backup 2: lib 3: scopy 4: scopy.ico 5: scopy.lpi 6: scopy.lpr 7: scopy.res 8: x bart@simenon:~/LazarusProjecten/ConsoleProjecten/scopy> However from inside my program I cannot distinguish between the followin 2 scenarios: 1: x is the last item in the list expanded by bash or 2: the commandline actually was "scopy * x" Scenario 1 is a syntax error, and it should not be treated as if it were scenario 2. Things get even more confusing when i use a syntax like scopy source dest excludefilter bart@simenon:~/LazarusProjecten/ConsoleProjecten/scopy> ./scopy * y *.bak 1: 123 2: 1233 3: 12333 4: 123.bak 5: 123.tmp 6: 456.bak 7: backup 8: lib 9: scopy 10: scopy.ico 11: scopy.lpi 12: scopy.lpr 13: scopy.res 14: x 15: y 16: 123.bak 17: 456.bak Obviously this is a common scenario on Linux, so how to treat it? I would prefer to expand the wildcards by myself, but it seems I have no access to what the user actually typed on the commandline? Bart _______________________________________________ fpc-pascal maillist - fpc-pascal@lists.freepascal.org http://lists.freepascal.org/mailman/listinfo/fpc-pascal
