On Sat, Nov 17, 2012 at 12:48 PM, leledumbo <leledumbo_c...@yahoo.co.id> wrote:
> Cross posted from stackoverflow:
> http://stackoverflow.com/questions/13431079/how-to-make-class-constructor-body-calls-descendants-overriden-method-property
>
> I'm writing an ORM framework and got stuck in a way to automatically
> determine table name from class name. In my base object for the ORM to work,
> I have:
>
> TghModel = class
> ...
> class var FTableName: String;
> class constructor Create;
> ...
>
> whose implementation is:
>
> class constructor TghModel.Create;
> begin
> FTableName := ClassName;
> Delete(FTableName,1,1); // Delete 'T'
> end;
>
> My assumption was that ClassName method will return the real class name.
> e.g. if I have:
>
> TUsers = class(TghModel)
>
> then FTableName will be initialized to TUsers instead of TghModel, which is
> wrong. I want to avoid users to make class constructor for each classes
> inheriting from TghModel, especially because the content would be totally
> the same as in TghModel.Create. Is there any way to implement it?
Tell the user of the framework to do something like this for every
class of your model:
initialization
TUser.RegisterClass;
TProduct.RegisterClass;
...
or
initialization
RegisterClasses([TUser, TProduct, ...]);
Btw I've tried the following code:
program Project1;
{$mode objfpc}{$H+}
type
TBase = class(TObject)
public
class var name: string;
end;
TConcrete = class(TBase);
begin
TBase.name := 'base';
TConcrete.name := 'concrete';
writeln('TBase.name: ', TBase.name);
end.
whose output is:
TBase.name: concrete
which means, if I'm not mistaken, the class var "name" is shared
between all decendants, so perhaps your approach won't work very well.
Please correct me if I'm wrong.
Joao Morais
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