On Sun, Jul 01, 2001 at 09:20:44PM -0700, Crist J. Clark wrote:
> Hmmm... Looks like,
>
> # syslogd -a 192.168.1.0/29
>
> Will work and,
>
> # syslogd -a 192.168.1.1/29
>
> Won't.
That's the standard behaviour of a netmask, isn't it? The usual
way to check if host h is in network/netmask n/m is to check if:
(h & m == n)
this means that the bits of the network which are not in the mask
must be zero.
David.
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