On 06/06/10 15:13, Dag-Erling Smørgrav wrote:
The second command will receive whatever is left after the first is
done.  Otherwise, read(1) loops wouldn't work.  You chose a poor
example, since cat(1) consumes*everything*.

Fair enough. My point remains though, using this technique is liable to lead to unpredictable results. :)


Doug

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