In message <[EMAIL PROTECTED]>, Warner Losh writes:
>Number 2. ANSI-C (aka c89) requires that free(NULL) work. We
>shouldn't go out of our way to pander to those machines where it
>doesn't.
The reason why this is so is that it is legal for
realloc(ptr, 0):
to return either a NULL pointer or a real pointer, and to remain
consistent, the following sequence should always be legal:
ptr = malloc(foo);
ptr = realloc(foo, bar);
free(ptr);
--
Poul-Henning Kamp | UNIX since Zilog Zeus 3.20
[EMAIL PROTECTED] | TCP/IP since RFC 956
FreeBSD committer | BSD since 4.3-tahoe
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