I tried the 'ln -s' command in bothe 4.3 & 4.7 in a situation where it should fail and it did, but it still had a return/exit code of 0 , I think it should have been nonzero. I tried 'ln -s a b' where the file b existed (and was a directory) and I wanted to create the file named a also pointing to it. The correct form was 'ln -s b a'.
FreeBSD 4.3-RELEASE FreeBSD 4.3-RELEASE #0: Sat Apr 21 \
10:54:49 GMT 2001 \ [EMAIL PROTECTED]:/usr/src/sys/compile/GENERIC i386
FreeBSD 4.7-RELEASE FreeBSD 4.7-RELEASE #0: Wed Oct 9 \
15:08:34 GMT 2002 \ [EMAIL PROTECTED]:/usr/obj/usr/src/sys/GENERIC \ i386 I don't have a 4.3 or 4.7 box, but on 4.11 I see: $ ls a.out a.out $ ln -s foo a.out ln: a.out: File exists $ echo $? 1 Are you really running /bin/ln? Do you run other programs at the time of displaying your PS1 prompt? -- FreeBSD Developer, http://people.freebsd.org/~jkoshy _______________________________________________ freebsd-hackers@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[EMAIL PROTECTED]"