1086 tor RET read 1568/0x620 1086 tor CALL clock_gettime(0xd,0x7fffffffd910) 1086 tor RET clock_gettime 0 1086 tor CALL kevent(0x3,0x3e18000,0x2,0x3dbe000,0x400,0x7fffffffd920) 1086 tor GIO fd 3 wrote 64 bytes
1086 tor RET kevent 3 1086 tor CALL clock_gettime(0x4,0x7fffffffd940) 1086 tor RET clock_gettime 0 1086 tor CALL gettimeofday(0x7fffffffd930,0) 1086 tor RET gettimeofday 0 1086 tor CALL recvfrom(0xbc2,0x4822020,0x3e40,0,0,0) 1086 tor GIO fd 3010 read 4096 bytes As I understand kevent to be part of queue I go with yes here. What I also take from it is a huge number of clock_gettime() and gettimeofday() calls. Julian Am 08.02.2012 um 17:39 schrieb Adrian Chadd: > Can you verify that it's properly using kqueue, rather than poll? > > > Adrian
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